I looked into how fat the wire going from stunt batteries to motor speed controllers needs to be. Results are interesting, but not too astonishing. I'd assumed that AWG 20 wire would suffice to carry the current with acceptable resistance loss, and that people are using AWG 12 or 14 wire for some Eli-the-ice-man* reason. However, it appears that inductance (the pertinent Eli-the-ice-man component) is a function of wire length, rather than thickness, and is maybe not a big deal even for length..
Is weight reduction from smaller wire worth the resistance penalty? Ideally, one would cipher airframe change due to weight and other esoteric stuff, but I took an easy way out. The upper left table in the attachment shows properties of three comparable battery species: 1) five Molicel P50B 2700-size LiIon cells, 2) six Molicel 18650-size LiIon cells, and 3) good old Thunder Power 2800 mAhr six-cell LiPos. The upper right table shows a trade between the latter two. Name-brand stunt fliers have decided that batteries of LiIon cells are better than those of LiPos. To wit, it's worth .066 ohms of internal resistance to lose 61 grams of battery: .00108 ohm/gram. The lower right table shows trades between 18-gauge wire and 14-gauge wire and between 20-gauge wire and 14-gauge wire. From 14-gauge to 18-gauge costs .00111 ohm/gram, so if it's worth changing from the LiPo battery to the LiIon battery, it's worth changing from 14-gauge wire to 18-gauge wire. Returns diminish for 20-gauge wire.
There are other considerations, e.g. 1) For a given connector, which size wire would require more solder? 2) It's easier to deal with thinner wire in a narrow fuselage. 3) Heat could be a problem with thin wire. At 20 amps, the average current for my Impact with a six-cell battery on a cool day at 200 ft. altitude, 18-gauge wire dissipates 2.6 watts/foot. 20-gauge wire dissipates 4.1 watts/foot. Peak current is more than 20 amps, and remembering the nursery rhyme, "Twinkle twinkle little star, power = I squared R," one might worry about melted insulation or charred paint. Even worse would be on a multi-motor airplane with high-kV motors and fewer cells.
*E = L dI/dt, I = C dE/dt