I did some cyphering, and it appears that Igor is correct, as usual. Work-- vortex energy in this case-- is force x distance. Induced drag is the amount of vortex energy an airplane puts into the air per unit distance along its path. Not counting induced drag due to lift to overcome gravity, the difference between the same airplane's induced drag going around a corner between the big prop and the little prop is proportional to the square of airspeed in the corner. So if the little prop allows the airplane to slow down more during the turn, the little-prop-powered airplane will put less wake into the air than same airplane with the big prop. Everything else cancels out. I figure (and please check this) that vortex energy per unit path length = induced drag = 2 m^2 V^2 / (pi e b^2 rho r^2) , where m = airplane mass, V = airspeed, e is the efficiency number = 1/the fraction of the airplane's induced drag over that of a wing with the same aspect ratio and an elliptical lift distribution, b= span, rho = air density, and r = loop radius. I doubt if the difference in prop wake energy between the two props matters much.
If you can do something to move the airplane's wake away from the maneuver path, the wake won't bother the airplane. For example, if somehow the prop blast entrains the wake and blows it away from the center of the loop, the airplane might not encounter the wake except at eight intersections, as Randy notes. So maybe this happens, and the little prop is better at blowing the wake away. I sure don't know.