More than you want to see I bet, but here is an over-simplified physics calculation of what is going on in a wingover (first half from pullup to first pullout. What is over--simplified is that I have NOT included any speed loss due to the sharp corner, and left out any type of outward thrust that might be present.
Also I am not sure about the actual level lap thrust. Here I am using a value that a propeller calculation gave me (from my "Pointy-head alert" thread of a couple of years ago). I am pretty confident about using the thrust vs airspeed part of the plot, but its the absolute magnitude that I am not sure of.
I assume that the drag at 24m/s (=54mph) just equals the level lap thrust, and then scale the drag as the square of the airspeed.
The graphic includes 2 plots, the left side one is the quantities vs the angle in the climb (0 degrees is level lap height at the beginning, 90 degrees is overhead, and 180 degrees would be the pullout height (but remember, I don't model the corners at all in this plot). The right side graph are the same quantities as a function of time. Note the Line tension uses the scale on the left vertical axis, and all other quantities use the scale on the right vertical axis).
Just for a quantity check 4.5 N (my level lap thrust) is about a pound of thrust.
I plot Line tension (white), airspeed (red in m/s)), Altitude (green in meters), Thrust from prop (blue in Newtons --N), Drag (yellow, also in N), and total tangential force (violet in N---just = (thrust-drag+-component of gravity in direction of thrust).
As Igor mentions, notice the maximum decelerating force (violet trace) is at 0 degrees, where gravity is pulling all its weight against you, and drag is still high and thrust relatively low. Also note maximum drag is at the pullout where airspeed is the highest.
Enjoy!